Time, Speed and Distance MCQs MCQs - Maths Practice | PakExamPoint

Practise Time, Speed and Distance MCQs MCQs in Maths. Attempt multiple-choice questions, check answers and revise related subtopics.

Time, Speed and Distance MCQs MCQs and revision practice

Study Time, Speed and Distance MCQs through multiple-choice questions in Maths. This subtopic contains 295 practice questions. Read the wording carefully, compare the options and attempt an answer before checking the solution in learning mode.

Use these Time, Speed and Distance MCQs MCQs to identify the facts, rules or methods you need to revise. Where an explanation is available, work through it and write down why your chosen option was correct or incorrect. Revisit difficult questions after reviewing your notes, then use exam mode for timed practice.

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Time, Speed and Distance MCQs: questions and answer review

Try each question before opening its answer. Record the concept behind each mistake and revisit it during your next practice session.

61. If a bus covers 240 km in 3 hours, what is its average speed in km/hr?

Check answer and explanation

Answer: 80 km/hr

Explanation To find the average speed, divide the total distance by the total time: Average speed = Total distance ÷ Total time = 240 km ÷ 3 hr = 80 km/hr So, the bus's average speed is 80 km/hr .

62. 445mm-198mm+250mm=______mm=____cm?

Check answer and explanation

Answer: 497 mm = 49.7 cm

Explanation 445 mm - 198 mm + 250 mm = ? Step 1: 445 - 198 = 247 mm Step 2: 247 + 250 = 497 mm Convert to cm: 497 mm = 49.7 cm

63. A train left Lahore at 9:32 a.m. and reached Peshawar at 5:23 p.m. How long did it take?

Check answer and explanation

Answer: 7 hours and 51 minutes

Explanation To find the duration of the train journey , subtract the start time from the arrival time: Arrival time: 5:23 p.m. Start time: 9:32 a.m. Convert both times to a 24-hour clock : Arrival time: 17:23 (5:23 p.m.) Start time: 09:32 (9:32 a.m.) Subtract the start time from the arrival time: 17:23 - 09:32 = 7 hours 51 minutes Therefore, the train journey took 7 hours and 51 minutes.

64. A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in

Check answer and explanation

Answer: 12 days

Explanation Let's solve step-by-step: - A’s rate = 1/15 work/day - B’s rate = 1/10 work/day Work done in the first 2 days (both A and B): (A + B) × 2 = (1/15 + 1/10) × 2 = (2/30 + 3/30) × 2 = (5/30) × 2 = (1/6) × 2 = 1/3 of the work. Remaining work after 2 days: 1 - 1/3 = 2/3 Time taken by A alone to complete the remaining work: Work = Rate × Time Time = Work / Rate = (2/3) / (1/15) = (2/3) × 15 = 10 days Total time to complete the work: 2 days (both working) + 10 days (A alone) = 12 days

65. A train covers 240 km at a uniform speed. If its speed is increased by 4 km/h, it takes 0.5 hour less. What is the original speed?

Check answer and explanation

Answer: 40 km/h

Explanation Time at original speed = 240 / x Time at increased speed = 240 / (x + 4) Given: 240/x - 240/(x + 4) = 0.5 Multiply through by x(x + 4) to eliminate denominators: 240(x + 4) - 240x = 0.5x(x + 4) 240x + 960 - 240x = 0.5x² + 2x 960 = 0.5x² + 2x Multiply both sides by 2: 1920 = x² + 4x x² + 4x - 1920 = 0 Solve the quadratic: x² + 4x - 1920 = 0 Using quadratic formula: x = [-4 ± √(16 + 7680)] / 2 x = [-4 ± √7696] / 2 √7696 ≈ 87.7 x ≈ (-4 + 87.7)/2 ≈ 83.7/2 ≈ 41.85 Approximate correct option is 40 km/h

66. A father was twice the age of her daughter 4 years ago. The sum of their ages is 47. What is the daughter's age today?

Check answer and explanation

Answer: 17

Explanation Let daughter's age = x Then father’s age = 47 - x 4 years ago: Father's age = 47 - x - 4 = 43 - x Daughter's age = x - 4 Given: Father was twice the daughter's age 4 years ago 43 - x = 2(x - 4) 43 - x = 2x - 8 43 + 8 = 3x ⇒ 51 = 3x ⇒ x = 17

67. If m:n = 3:2, the (4m+5n):(4m-5n) is equal to _____?

Check answer and explanation

Answer: 11:1

Explanation To solve this, we can start by expressing the given ratio m:n = 3:2 in terms of a variable, let's say x. So, m = 3x and n = 2x. Now, let's substitute these expressions into the given ratio (4m+5n):(4m-5n): (4(3x) + 5(2x)) : (4(3x) - 5(2x)) Expanding and simplifying, we get: (12x + 10x) : (12x - 10x) 22x : 2x Now, we can divide both terms by 2x to get: 11 : 1

68. A car travels at a speed of 65 miles per hour. How far will it travel in 5 hours?

Check answer and explanation

Answer: 325

Explanation Given the speed of the car is 65 miles per hour: Step 1: Calculate the distance traveled in 5 hours. Distance = Speed × Time = 65 × 5 = 325

69. A can type 10 pages in 5 minutes. B can type 5 pages in 10 minutes. Working together, how many pages can they type in 30 minutes?

Check answer and explanation

Answer: 75

Explanation Efficiency of A = 10/5 =2 Efficiency of B = 5/10 = 0.5 No of page typed by A in 30 min = 30 x 2 = 60 No of page typed B in 30 min = 30 x 0.5 = 15 total page together is 60 + 15 = 75

70. 187 m - 95 m + 328 m = ? (in cm)

Check answer and explanation

Answer: 42,000 cm

Explanation 187 m - 95 m + 328 m = 420 m 420 m = 420 × 100 = 42,000 cm

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