Practise Average MCQs Math MCQs in Maths. Attempt multiple-choice questions, check answers and revise related subtopics.
Study Average MCQs Math through multiple-choice questions in Maths. This subtopic contains 480 practice questions. Read the wording carefully, compare the options and attempt an answer before checking the solution in learning mode.
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Answer: 90
Explanation Total height of 60 = 150 × 60 = 9000 cm Total height of 40 = 180 × 40 = 7200 cm Total height of 20 = 9000 - 7200 = 1800 cm Average of 20 = 1800/20 = 90 cm Last verified on 07-03-2026
Answer: both male and female are failed
Explanation You’re talking about one class. There are 95 students in the class. You’re presenting with two statements 80% of the class failed in Chemistry 30% of the class failed in English Logic "It means both boys and girls in the class failed, no matter whether they failed in chemistry or English"
Answer: 3
Explanation Let the three numbers be x,y,z (x+y)/2=2 (y+z)/2=3 (x+z)/2=4 from all equations, x+y=4 y+z=6 x+z = 8 Add all equations 2(x+y+z) = 18 x+y+z = 9 Avg of 3 nos = (x+y+z)/3 = 9/3 = 3 ND5-07-2023
Answer: 12
Explanation Find HCF of 408, 468, and 516 Prime factorizations: 408 = 2 3 ⋅ 3 468 = 2 2 ⋅ 3 ⋅ 13 2^2 cdot 3 cdot 13 516 = 2 2 ⋅ 3 ⋅ 43 Common: 2^ 2.3 = 4.3=12
ایک مخصوص کلاس میں، 24 میں سے 3 طلباء تنظیموں میں ہیں۔ طلباء تنظیموں میں طلباء اور طلباء تنظیموں میں طلباء کا تناسب کیا ہے؟
Answer: 1/7
Explanation If 3 out of 24 students are in student organizations, then 21 are not. So the ratio of in and not in is 3:21 1:7. SH31-8-2023
Answer: 57
Explanation Since the student who left weighed 45 kgs, the total weight of all 60 students (including the student who left) is 59x + 45. When the student left, the average weight of the remaining 59 students increased by 200g (or 0.2 kgs), so we can set up the equation: 59x + 45 = 60(x - 0.2) Simplifying the equation, we get: 59x + 45 = 60x - 12 Solving for x, we get: x = 57 So, the correct answer is: 57
Answer: 1 hour
Explanation Equation Setup: In bad weather: 600 = (v - 200)(t + 0.5) 600 = ( v − 200 ) ( t + 0.5 ) In good weather: 600 = v t Solving for v v v = 600/t Substituting v v v in the first equation: 600 = left(frac{600}{t} - 200right)(t + 0.5) 600 = ( t 600 − 200 ) ( t + 0.5 ) Expanding and simplifying the equation: 600t = 600t + 300 - 200^2 - 100t 600 t = 600 t + 300 − 20 0^ 2 − 100 t -200t^2 - 100t + 300 = 0 − 200 t&^ 2 − 100 t + 300 = 0 2t^2 + t - 3 = 0 2 t^ 2 + t − 3 = 0 Solving the quadratic equation: 2t^2 + 3t - 2t - 3 = 0 2 t^ 2 + 3 t − 2 t − 3 = 0 2t(t - 1) + 3(t - 1) = 0 2 t ( t − 1 ) + 3 ( t − 1 ) = 0 (2t + 3)(t - 1) = 0 ( 2 t + 3 ) ( t − 1 ) = 0 Finding values for t t t : 2t + 3 = 0 quad text{or} quad t - 1 = 0 2 t + 3 = 0 or t − 1 = 0 2 t = − 3 ⇒ t = − 2 3 (negative, not possible) t = 1 quad text{(valid answer)} t = 1 (valid answer)
10 اقدار کا اوسط 200 ہے۔ ان میں سے نو کا مجموعہ 1850 ہے۔ 10 واں اصول تلاش کریں۔
Answer: 150
Explanation Sh5-9-2023 1069.31x900.979 (Original: 1080x91
Answer: 83 days
Explanation 5 men = 50 days 1 man = 5 × 50 = 250 days 3 men = 250/3 = 83.33 days Last verified on 02-03-2026
Answer: 160
Explanation The total food required for x x x cows over 150 days is: Total food = x × 150 When the number of cows is reduced by 10, i.e., x - 10 x − 10 , the food lasts for 10 more days, meaning it lasts for 160 days. So, the total food required for x-10 cows over 160 days is: Total food = ( x − 10 ) × 160 Since the total amount of food remains constant in both cases, we can equate the two expressions for total food: x x × 150 = ( x − 10 ) × 160
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