Time, Speed and Distance MCQs MCQs - Maths Practice | PakExamPoint

Practise Time, Speed and Distance MCQs MCQs in Maths. Attempt multiple-choice questions, check answers and revise related subtopics.

Time, Speed and Distance MCQs MCQs and revision practice

Study Time, Speed and Distance MCQs through multiple-choice questions in Maths. This subtopic contains 295 practice questions. Read the wording carefully, compare the options and attempt an answer before checking the solution in learning mode.

Use these Time, Speed and Distance MCQs MCQs to identify the facts, rules or methods you need to revise. Where an explanation is available, work through it and write down why your chosen option was correct or incorrect. Revisit difficult questions after reviewing your notes, then use exam mode for timed practice.

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Time, Speed and Distance MCQs: questions and answer review

Try each question before opening its answer. Record the concept behind each mistake and revisit it during your next practice session.

51. If 1 man writes 5 papers in 5 minutes, then 1 man will write 1 paper in?

Check answer and explanation

Answer: 1 minute

Explanation Given: 1 man writes 5 papers in 5 minutes . We are asked: How long will 1 man take to write 1 paper? Step 1: Find the time for 1 paper Total papers = 5 Total time = 5 minutes Time per paper = Total time ÷ Number of papers Time per paper = 5 minutes/5 ​ = 1 minute

52. The distance between two trains is 150km having one train speed 60km/h and other is 40km/h. What will be time they can meet in hour? 1

Check answer and explanation

Answer: 1 hour 30 minutes

Explanation When two objects are moving towards each other, their relative speed is the sum of their individual speeds. Speed of the first train = 60 km/h Speed of the second train = 40 km/h Distance between them = 150 km The relative speed is: 60 km/h + 40 km/h = 100 km/h 60 , text{km/h} + 40 , text{km/h} = 100 , text{km/h} Now, to find the time it takes for the trains to meet, use the formula: Time = Distance Relative Speed text{Time} = frac{text{Distance}}{text{Relative Speed}} ​ Time = 150 km 100 km/h = 1.5 hours = 1 hour 30 minutes text{Time} = frac{150 , text{km}}{100 , text{km/h}} = 1.5 , text{hours} = 1 , text{hour} , 30 , text{minutes} Time = 150 km/ 100 km ​/h = 1.5 hours = 1 hour 30 minutes

53. If 5 cats catch 5 miles in 5 minutes, how many cats are needed to catch 100 miles in 100 minutes?

Check answer and explanation

Answer: 5

Explanation 5 cats catch 5 mice in 5 minutes → that means 5 cats = 1 mouse per minute (since 5 mice / 5 minutes = 1 mouse per minute). So, 1 cat = 1/5 mouse per minute. Now, in 100 minutes: 1 cat catches = 1/5 × 100 = 20 mice. So, 5 cats will catch 20 × 5 = 100 mice in 100 minutes.

54. The angle of depression of a point situated at a distance of 70m from the base of a tower is 60. the height of the tower is?

Check answer and explanation

Answer: 70 square root 3m

Explanation In this scenario, we can use the tangent function, which is the ratio of the opposite side (height of the tower, h) to the adjacent side (the horizontal distance, 70m):

55. If a runs less fast than b and b run fast but not faster than c then as compared to A, C runs

Check answer and explanation

Answer: Faster than A

Explanation A runs less fast than B → B is faster than A. B runs fast but not faster than C → This means B is either equal to or slower than C. From this, we can conclude: If B is already faster than A and C is at least as fast as B, then C is definitely faster than A . Final Answer: C runs faster than A

56. How many hours are there in 2700 minutes ?

Check answer and explanation

Answer: 45 hours

Explanation 2700÷60= 45

57. 10 men can complete a job in 14 days. How long will it take 4 men to finish the same job if the same at the same rate?

Check answer and explanation

Answer: 35 days

Explanation 10 men complete a job in 14 days, so the total work equals 10 men × 14 days. With 4 men, the work remains the same, but takes longer. Multiply the original duration by the ratio of men: 14 days × (10/4) = 35 days. Therefore, 4 men take 35 days to finish the job at the same rate.

58. If a person starts from home to school at a speed of 3 km/hr and returns back home at a speed of 2 km/hr in a total of 5 hours, what is the distance between home and school?

Check answer and explanation

Answer: 6 km

Explanation Let's break this problem down step by step: Let the distance between home and school be x km. Time taken to go to school = Distance / Speed = x / 3 Time taken to return home = Distance / Speed = x / 2 Total time = 5 hours, so we can set up the equation: x / 3 + x / 2 = 5 To solve for x, we can find a common denominator (6) and add the fractions: (2x + 3x) / 6 = 5 Combine like terms: 5x / 6 = 5 Multiply both sides by 6 to eliminate the fraction: 5x = 30 Divide both sides by 5 to solve for x: x = 6 So, the correct answer is: 6 km

59. If 8 men or 12 women can do a piece of work in 25 days, in how many days can the same work be done by 6 men and 11 women?

Check answer and explanation

Answer: 15 days

Explanation Work done by 8 men or 12 women in 25 days: Work done by 8 men in 25 days = 1 complete piece of work. Work done by 12 women in 25 days = 1 complete piece of work.

60. How many times do the hands of a clock coincide in a day?

گھڑی کے ہاتھ ایک دن میں کتنی بار ملتے ہیں؟

Check answer and explanation

Answer: 22

Explanation The hands of a clock coincide 22 times in a 24-hour day. The hour and minute hands coincide once every 65 minutes (60 minutes + 5 minutes). Since there are 24 hours in a day , the hands coincide 24 x (24/65) = 22 times in a 24-hour day.

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