Time, Speed and Distance MCQs MCQs - Maths Practice | PakExamPoint

Practise Time, Speed and Distance MCQs MCQs in Maths. Attempt multiple-choice questions, check answers and revise related subtopics.

Time, Speed and Distance MCQs MCQs and revision practice

Study Time, Speed and Distance MCQs through multiple-choice questions in Maths. This subtopic contains 295 practice questions. Read the wording carefully, compare the options and attempt an answer before checking the solution in learning mode.

Use these Time, Speed and Distance MCQs MCQs to identify the facts, rules or methods you need to revise. Where an explanation is available, work through it and write down why your chosen option was correct or incorrect. Revisit difficult questions after reviewing your notes, then use exam mode for timed practice.

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Time, Speed and Distance MCQs: questions and answer review

Try each question before opening its answer. Record the concept behind each mistake and revisit it during your next practice session.

121. A train travels 225 km in 3.5 hours and 370 km in 5 hours. Find the average speed of train?

Check answer and explanation

Answer: 70 km/h

Explanation Total distance = 225 + 370 = 595 km Total time = 3.5 + 5 = 8.5 hours Average speed = 595/8.5 = 70 km/h Last verified on 02-04-2026

122. If a bus covers 120 km in 3 hours, find the speed of the bus in km/hr?

Check answer and explanation

Answer: 40 km/hr

Explanation To find the speed of the bus, we can use the formula: Speed = Distance / Time Plugging in the values given: Speed = 120 km / 3 hr Speed = 40 km/hr

123. 20 men can construct a building in 40 days. How long will it take 10 men to do this work?

Check answer and explanation

Answer: 80 days

Explanation 20 men can construct a building in 40 days. Total work = 20 men × 40 days = 800 man-days. Time = Total work / Number of men = 800 man-days / 10 men = 80 days.

124. A train covers 40 km in 1 hour. How much distance will it cover in 8 minutes?

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Answer: 5.33 km

Explanation Distance in 1 hour = 40 km Time given = 8 minutes = 8/60 hours = 2/15 hours Distance = Speed × Time Distance = 40 × 2/15 = 80/15 = 5.33 km

125. How many times is a right angle formed by a clock’s hand in a day?

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Answer: 48

Explanation - A clock's hands form a right angle 2 times every hour (once when the minute hand is ahead of the hour hand, and once when it's behind). - In 12 hours, right angles occur: 2 × 12 = 24 times - In 24 hours (a full day): 24 × 2 = 48 times

126. How many times in a day are the hands of clock in straight line but opposite in direction?

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Answer: 22 times

Explanation The hands of a clock point in opposite directions (in the same straight line) 11 times in every 12 hours. So, in a day, the hands point in the opposite directions 22 times .

127. A racing car is speeding around a flat, unbanked circular track whose radius is 250 meters. The car's speed is a constant 50.0 meters per sound. The mass of the Car is 2.00 x 10^3 kilograms. The centripetal force necessary to keep the car in its circular path is provided by _________?

Check answer and explanation

Answer: friction

Explanation The centripetal force necessary to keep the racing car in its circular path is indeed provided by friction between the tires of the car and the track. Concept: When the car is moving in a circular path, it experiences an inward acceleration towards the center of the circle. This acceleration is called the centripetal acceleration. According to Newton's second law of motion, the net force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the net force is the centripetal force, and the centripetal acceleration can be calculated using the formula: a_c = v^2 / r Where: - a_c is the centripetal acceleration - v is the speed of the car - r is the radius of the circular track Substituting the given values into the formula: a_c = (50.0 m/s)^2 / 250 m Simplifying the equation: a_c = 2500 m^2/s^2 / 250 m a_c = 10 m/s^2 The centripetal force required to keep the car in its circular path is equal to the product of the car's mass and the centripetal acceleration. Using the given mass of the car: F = (2.00 x 10^3 kg) * (10 m/s^2) Simplifying the equation: F = 2.00 x 10^4 N Therefore, the centripetal force necessary to keep the car in its circular path is provided by friction and its value is 2.00 x 10^4 Newtons.

128. If a bus travels 150 meters in 15 seconds, what is its speed?

Check answer and explanation

Answer: 10 m/s

Explanation Speed = 150 m ​/ 15 s = 10 m/s

129. A man starts climbing a hill. Every minute he ascends 20-yards but slips down 5-yards. How long will he take to ascend a point of 80-yards high?

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Answer: 6 minutes

Explanation Every minute: Climbs 20 yards, slips 5 yards → Net gain = 15 yards/min In 5 minutes, net gain = 15 × 5 = 75 yards In the 6th minute, he climbs a full 20 yards to reach 95 yards, but we only need to reach 80 yards → So in the 6th minute, he climbs from 75 to 80 yards in (5/20 = 0.25) min = 15 seconds

130. The virus spreads rapidly in the town. It infected the people - First day: 8, Second day: 16, Third day: 32. What will be the number of people infected on the next day?

Check answer and explanation

Answer: 64 people

Explanation The pattern shows the number of infected people is doubling each day: - Day 1: 8 - Day 2: 16 (8 × 2) - Day 3: 32 (16 × 2) So, Day 4 will be: 32 × 2 = 64 people

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