Practise Quantitative Reasoning MCQs in Maths. Attempt multiple-choice questions, check answers and revise related subtopics.
Study Quantitative Reasoning through multiple-choice questions in Maths. This subtopic contains 193 practice questions. Read the wording carefully, compare the options and attempt an answer before checking the solution in learning mode.
Use these Quantitative Reasoning MCQs to identify the facts, rules or methods you need to revise. Where an explanation is available, work through it and write down why your chosen option was correct or incorrect. Revisit difficult questions after reviewing your notes, then use exam mode for timed practice.
Continue your revision with related topics: 100 Most Repeated MCQs of Math MCQs, Algebra MCQs MCQs, Analogy MCQs MCQs, Average MCQs Math MCQs, Basic Math MCQs, Direction Sense MCQs MCQs, Geometry MCQs MCQs, IQ Past Papers MCQs MCQs.
Return to all Maths topics to choose your next area of study. Read the MCQ study guide to plan your revision, or try a Maths practice quiz.
Try each question before opening its answer. Record the concept behind each mistake and revisit it during your next practice session.
Answer: 2.4
Explanation Step 1: Find one-tenth of 120 frac{1}{10} times 120 = 12 1/10 × 120 = 12 Step 2: Find 20% of 12 20% of 12 = 20 /100 × 12 = 0.2 × 12 = 2.4
Answer: Decrease
Explanation Assume price = 100 After +20% → 120 After −20% → 96 So the final price is less than the original . Last updated by NA on 23-April-2026
Answer: 5
Explanation 5 + 5 − 5 × 5 ÷ 5 Step 1: Solve multiplication/division first (from left to right) 5 × 5 = 25 25 ÷ 5 = 5 So the expression becomes: 5 + 5 − 5 Step 2: Solve addition/subtraction from left to right 5 + 5 = 10 10 − 5 = 5 So, the answer is 5.
Answer: 120
Explanation =3/4 of 160 = (3 ÷ 4) × 160 = 120 . Last updated on 09-03-2026
Answer: 3
Explanation log₁₀(1000) means “10 raised to what power gives 1000?” Since 10³ = 1000, log₁₀(1000) = 3.
Answer: 5/√34
Explanation 1 + tan 2 x = sec 2 x 1 + tan^2 x = sec^2 x 1 + tan 2 x = sec 2 x sec x = √(1 + (3/5)²) = √(34/25) = √34/5 cos x = 1/sec x = 5/√34
Answer: 15
Explanation A number divisible by both 3 and 5 must be a common multiple of 3 and 5. The smallest common multiple (LCM) is: Multiples of 3 : 3, 6, 9, 12, 15 , 18… Multiples of 5 : 5, 10, 15 , 20… The f irst common number is 15 . Last updated 11-02-2026
Answer: 325
Explanation Step 1: Write as an equation 0.56 × Y = 182 Step 2: Solve for Y Y = 182/ 0.56 Step 3: Divide Y = 325 Answer: Y = 325
Answer: 15
Explanation Let the youngest brother’s age = x Ali is twice as old , so Ali’s age = 2x Difference between their ages = 15 2 x − x = 15 x = 15 Last updated on 06-March-2026
Answer: 41/40
Explanation Given (Sinθ + Cosθ) / (Sinθ - Cosθ) = 4/5 Let’s call this ratio R = 4/5. We can write: R = (Sinθ + Cosθ) / (Sinθ - Cosθ) Multiply numerator and denominator by (Sinθ - Cosθ): R = [(Sinθ + Cosθ)(Sinθ - Cosθ)] / (Sinθ - Cosθ)² But better approach is: Square both numerator and denominator: R² = (Sinθ + Cosθ)² / (Sinθ - Cosθ)² Calculate numerator: (Sinθ + Cosθ)² = Sin²θ + 2SinθCosθ + Cos²θ = 1 + 2SinθCosθ Denominator: (Sinθ - Cosθ)² = Sin²θ - 2SinθCosθ + Cos²θ = 1 - 2SinθCosθ So, R² = (1 + 2SinθCosθ) / (1 - 2SinθCosθ) Given R = 4/5, so R² = 16/25 Set: 16/25 = (1 + 2SinθCosθ) / (1 - 2SinθCosθ) Cross-multiplied: 16(1 - 2SinθCosθ) = 25(1 + 2SinθCosθ) 16 - 32SinθCosθ = 25 + 50SinθCosθ Bring terms together: -32SinθCosθ - 50SinθCosθ = 25 -16 -82SinθCosθ = 9 SinθCosθ = -9/82 Now, Tan²θ = (Sin²θ) / (Cos²θ) Recall identity: Tan²θ + 1 = sec²θ and (Tan²θ + 1) / (Tan²θ - 1) is the required expression. This requires more complex steps, but the given answer is 41/40.
Found a mistake? Use “Report correction” in the practice tool or contact us with the question and a supporting source.