Practise Time, Speed and Distance MCQs MCQs in Maths. Attempt multiple-choice questions, check answers and revise related subtopics.
Study Time, Speed and Distance MCQs through multiple-choice questions in Maths. This subtopic contains 295 practice questions. Read the wording carefully, compare the options and attempt an answer before checking the solution in learning mode.
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Answer: 16.5 meters
Explanation The total height of the tree = Eye-level height + Distance from eyes to top = 1.5 m + 15 m = 16.5 meters
Answer: 1.0 x 10^4 N
Explanation To calculate the force exerted by the pavement on the tires, we can use the centripetal force formula: Force (F) = (Mass (m) * Velocity squared (v^2)) / Radius (r) Given: Mass (m) = 1000 kg Velocity (v) = 10 m/s Radius (r) = 10 m Calculate the centripetal force (F): Using the formula, F = (m * v^2) / r, we can substitute the given values to find the force: F = (1000 kg * (10 m/s)^2) / 10 m F = 100,000 N / 1.0 x 10^4 N
Answer: 2xy
Explanation In the first y hours, the carpenter lays xy bricks. In the 2y hours thereafter, he lays (x/2)(2y) = xy bricks. Altogether, that's xy + xy = 2xy bricks.
Answer: 5.5 hour
Explanation Given Information: A lifter loads 200 packages per hour. A labor loads two quarters (i.e., 2/4 or 1/2) less than 200 packages per hour. 1 /2 × 200 = 100 So, the labor loads 200 - 100 = 100 packages per hour. Together, the lifter and labor load: 200 + 100 = 300 packages per hour They need to load 1500 packages. They take 30 minutes (0.5 hours) rest after every 2 hours of loading. Step 1: Calculate Total Loading Time Without Breaks 1500/3 00 = 5 hours So, if they were working continuously, they would need exactly 5 hours . Step 2: Account for Breaks They work for 2 hours , then take a 30-minute (0.5-hour) break . In 2 hours, they load: 2 × 300 = 600 packages After 2 hours, they take a 0.5-hour break . Continuing this cycle: First 2 hours: 600 packages (then a 30-minute break ) Next 2 hours: 600 packages (then a 30-minute break ) Remaining: 300 packages, which takes 1 more hour (no need for another break). Total time including breaks: 2 + 0.5 + 2 + 0.5 + 1 = 5.5 hours Step 3: Select the Correct Answer ( b ) 5.5 hours
Answer: 250 meter
Explanation The relative speed of the two trains is the sum of their individual speeds, since they're moving in opposite directions: 62 km/h + 40 km/h = 102 km/h Convert the relative speed from km/h to m/s: 102 km/h x (1000 m / 3600 s) = 28.33 m/s (approximately) The time it takes for the trains to cross each other is given as 18 seconds. The total distance covered by the trains during this time is the sum of their lengths. Let's call the length of the other train "x". Then, the total distance = 260 m + x Since the relative speed is 28.33 m/s, the total distance can also be calculated as: Total distance = Relative speed x Time = 28.33 m/s x 18 s = 510 m Equate the two expressions for total distance: 260 m + x = 510 m Solve for x: x = 510 m - 260 m = 250 m
Answer: 52.5 days
Explanation Work = Men × Days So, 105 men × 45 days = 4725 man-days Now, if 90 men are doing the same work: 4725 man-days ÷ 90 men = 52.5 days
Answer: 0.6 m
Explanation The car goes 8 km = 8000 meters in 4000 rounds. So, one round = 8000 ÷ 4000 = 2 meters. This is the circumference of the tire. Now, Diameter = Circumference ÷ 3.14 = 2 ÷ 3.14 ≈ 0.64 m, nearly 0.6 m .
Answer: 8
Explanation Let work done by P in 1 day = p work done by Q in 1 day =q Work done by R in 1 day = r p + q = 1/8 —(1) q + r= 1/12 —(2) p+ q+ r = 1/6 —(3) (3) – (2) => p = 1/6 – 1/12 = 1/12 (3) – (1) => r = 1/6 – 1/8 = 1/24 p + r = 1/12 + 1/24 = 3/24 = 1/8 => P and R will finish the work in 8 days.
Answer: 30 days
Explanation
Answer: 255 km
Explanation To find the distance: Speed = 60 km/hr Time = 4 hours 15 minutes = 4.25 hours (convert 15 minutes to hours) Distance = Speed × Time = 60 km/hr × 4.25 hr = 255 km
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