Time, Speed and Distance MCQs MCQs - Maths Practice | PakExamPoint

Practise Time, Speed and Distance MCQs MCQs in Maths. Attempt multiple-choice questions, check answers and revise related subtopics.

Time, Speed and Distance MCQs MCQs and revision practice

Study Time, Speed and Distance MCQs through multiple-choice questions in Maths. This subtopic contains 295 practice questions. Read the wording carefully, compare the options and attempt an answer before checking the solution in learning mode.

Use these Time, Speed and Distance MCQs MCQs to identify the facts, rules or methods you need to revise. Where an explanation is available, work through it and write down why your chosen option was correct or incorrect. Revisit difficult questions after reviewing your notes, then use exam mode for timed practice.

Continue your revision with related topics: 100 Most Repeated MCQs of Math MCQs, Algebra MCQs MCQs, Analogy MCQs MCQs, Average MCQs Math MCQs, Basic Math MCQs, Direction Sense MCQs MCQs, Geometry MCQs MCQs, IQ Past Papers MCQs MCQs.

Return to all Maths topics to choose your next area of study. Read the MCQ study guide to plan your revision, or try a Maths practice quiz.

Time, Speed and Distance MCQs: questions and answer review

Try each question before opening its answer. Record the concept behind each mistake and revisit it during your next practice session.

11. Ali runs for 480 meters at the speed of 4 meters per second, He gets tried and rests for 10 minutes/ he runs again 300 meters at a speed of 5 meters per second and finishes. How many minutes did he take to finish the marathon?

Check answer and explanation

Answer: 13

Explanation

12. If the speed of the train is double that of a car and a car travels 30km in one hour how much distance will a train cover in 30 minutes?

Check answer and explanation

Answer: 30 km

Explanation Car speed = 30 km per hour Train speed = Double of car speed = 2 × 30 = 60 km per hour Time given = 30 minutes = ½ hour Distance covered by train = Speed × Time = 60 × ½ = 30 km Last updated 05-03-2026

13. A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?

Check answer and explanation

Answer: 36 Sec

Explanation Speed of train relative to jogger = (45−9) km/hr = 36 km/hr = (36×185​)m/sec = 10 m/sec. Distance to be covered = (240+120)m=360m. ∴ Time taken =(10360​)sec =36sec.

14. A train left a station at 8:35 a.m and arrived at its destination at 3:12 p.m. How long did the journey take?

Check answer and explanation

Answer: 6 hours and 37 minutes

Explanation Departure: 8:35 a.m. Arrival: 3:12 p.m. Convert both times to 24‑hour format: - 8:35 a.m. → 08:35 - 3:12 p.m. → 15:12 Difference: 15:12 − 08:35 → (15 – 8) hours = 6 hours → (12 – 35) minutes = –23 minutes → Borrow 1 hour → 6 hours → 5 hours 60 minutes → 60 – 23 = 37 minutes Total journey: 6 hours 37 minutes Last verified on 18-01-2026

15. Two trains, each of length 500 meters, start off from rest with speeds of 60 km/h and 45 km/h respectively. After how many minutes does the first train cross the second one?

Check answer and explanation

Answer: 2

Explanation Convert the speeds of the trains from km/h to m/s 1 km/h = 1000 m/3600 s Speed of the first train = 60 km/h = (60,000 m/3600 s) m/s = 16.67 m/s. Speed of the second train = 45 km/h = (45,000 m/3600 s) m/s = 12.50 m/s. Relative speed = Speed of the first train - Speed of the second train = 16.67 m/s - 12.50 m/s = 4.17 m/s. Distance = Length of the second train = 500 meters. Using the formula: Distance = Speed × Time Time = Distance / Relative speed = 500 meters / 4.17 m/s = 120.05 seconds. To convert the time from seconds to minutes, we divide by 60: Time in minutes = 120.05 seconds / 60 = 2 minutes (approximately). Therefore, the first train will cross the second train after approximately 2 minutes.

16. Two taps X and Y can fill a tank in 10 hrs. and 15 hours respectively. If the both taps are opened together, the tank will be full in?

Check answer and explanation

Answer: 6 hours

Explanation Tap X can fill the tank in 10 hours, which means it fills 1/10 of the tank per hour. Tap Y can fill the tank in 15 hours, which means it fills 1/15 of the tank per hour. When both taps are opened together, their combined rate of filling the tank is the sum of their individual rates: (1/10 + 1/15) of the tank per hour To add these fractions, we need a common denominator, which is 30. So we get: (3/30 + 2/30) = 5/30 = 1/6 of the tank per hour Since they fill 1/6 of the tank per hour together , they will fill the entire tank in 6 hours.

17. A car that gets 15 miles per gallons of gasoline can travel 250 miles on a full tank. If the same car got 20 miles per gallon, how many miles could it travel on a full tank?

Check answer and explanation

Answer: 333.4

Explanation Full tank capacity = Distance ÷ Miles per gallon = 250 miles ÷ 15 miles/gallon = 16.67 gallons (approximately) Now, if the car gets 20 miles per gallon, we can calculate the distance it can travel on a full tank: Distance = Full tank capacity × Miles per gallon = 16.67 gallons × 20 miles/gallon = 333.4 miles

18. Zohaib and Ali depart from point X. Zohaib goes North and covers 3 km then turns right and covers 4 km. All goes West and covers 5 km, then turns right and cover 3 km. How far is Zohaib from Ali?

Check answer and explanation

Answer: 9 km

Explanation Zohaib's Path : Starts at point X, goes Then turns right (East) and covers 4 km. So, Zohaib ends up 3 km North and 4 km East of point X. Ali's Path : Starts at point X, goes West 5 km. Then turns right (North) and covers 3 km. So, Ali ends up 3 km North and 5 km West of point X. Relative Positions : Zohaib is at (4, 3) for point X (East, North). Ali is at (-5, 3) concerning point X (West, North).

19. A can finish a work in 40 days. 5 is 255% less efficient then A. The number of days A & B will take to finish the work working together in nearly ≠ 3?

Check answer and explanation

Answer: None of these

Explanation To solve the problem, follow these steps: 1: Determine B's efficiency compared to A: A can finish the work in 40 days, so A's work rate is 1/ 40 of the work per day. If B is 255% less efficient than A, it means B's efficiency is reduced by 255%, which implies B is not practically effective (usually considered inefficient or not working effectively in real terms). 2: Calculate B's efficiency: If B is 255% less efficient , B's effective efficiency would be negative , which isn't practically feasible. To make sense of this: Assume B’s efficiency is effectively lower compared to A i n realistic scenarios. 3: Adjust B's effective efficiency for practical calculations: Let's use a model where B is significantly less efficient but not zero. For instance, if B’s efficiency is assumed to be around 10% of A’s for simplicity: B can do the work in approximately 400 days. The closest feasible answer given practical scenarios and combined work rate calculations is None.

20. A train running at the speed of 60 km | hr crosses a pole in 9 seconds. What is the length of the train?

Check answer and explanation

Answer: 150 metres

Explanation Speed = 60 km/hr = 60 × (5/18) m/s = 50/3 m/s Time = 9 seconds Length = Speed × Time = (50/3) × 9 = 150 meters Last verified on 04-04-2026

Found a mistake? Use “Report correction” in the practice tool or contact us with the question and a supporting source.