Time, Speed and Distance MCQs MCQs - Maths Practice | PakExamPoint

Practise Time, Speed and Distance MCQs MCQs in Maths. Attempt multiple-choice questions, check answers and revise related subtopics.

Time, Speed and Distance MCQs MCQs and revision practice

Study Time, Speed and Distance MCQs through multiple-choice questions in Maths. This subtopic contains 295 practice questions. Read the wording carefully, compare the options and attempt an answer before checking the solution in learning mode.

Use these Time, Speed and Distance MCQs MCQs to identify the facts, rules or methods you need to revise. Where an explanation is available, work through it and write down why your chosen option was correct or incorrect. Revisit difficult questions after reviewing your notes, then use exam mode for timed practice.

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Time, Speed and Distance MCQs: questions and answer review

Try each question before opening its answer. Record the concept behind each mistake and revisit it during your next practice session.

181. Two trains are moving in opposite directions at 60 km-hr and 90 km-hr. Their lengths are 1.10 km and 0.9 km respectively. What is the time taken by the slower train to cross the faster train in seconds?

Check answer and explanation

Answer: 48 seconds

Explanation Speed of the two trains: 60 km/hr and 90 km/hr If train cross each other, then effective speed = 60 + 90 = 150 km/hr Length of first train = 1.10 km or 1100 m Length of second train = 0.9 km or = 900 m formula Speed = Distance/Time ⇒ 150 × (5/18) = 2000/Time ⇒ 125/3 = 2000/Time ⇒ Time = 2000 × (3/125) ∴ Time = 48 seconds. Relative speed = 60 + 90 = 150 km/hr. = 150 x 5/18 = 125/3 m/sec. Distance covered = 1.10 + 0.9 = 2 km = 2000 m. Required time = 2000 x 3/125 = 48 sec.

182. A missile hit a 3000 km distant target in 45 minutes, the speed of the missile in km/h is _____?

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Answer: 4000 km/h

Explanation Speed is calculated using the formula: Speed = Distance / Time. Given distance = 3000 km and time = 45 minutes (0.75 hours), Speed = 3000 ÷ 0.75 = 4000 km/h .

183. A 600 m long train crosses a point in 30 seconds. What is the speed of the train in km/h?

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Answer: 72 km/h

Explanation Speed = Distance / Time = 600 m / 30 s = 20 m/s Convert to km/h: 20 × 3.6 = 72 km/h

184. What is the speed of a car that travels 700 km in 3 hours and 30 minutes?

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Answer: 200 km/h

Explanation To find the speed of the car, we need to divide the distance traveled (700 km) by the time taken (3 hours 30 minutes). First, let's convert the time from hours and minutes to just hours: 3 hours 30 minutes = 3.5 hours (converting 30 minutes to 0.5 hours) Now, let's calculate the speed: Speed = Distance ÷ Time = 700 km ÷ 3.5 hours = 200 km/h So, the correct answer is: 200 km/h

185. Mean height of 20 boys and 15 girls is 161 cm. Mean height of 14 girls is 151 cm. What is the mean height of 20 boys?

Check answer and explanation

Answer: 169 cm

Explanation Total students = 35 → Total height = 35 × 161 = 5635 cm 14 girls = 14 × 151 = 2114 cm So, 15 girls = (2114 + x) → x = height of 1 girl = assume x = 151 Total height of 15 girls ≈ 15 × 151 = 2265 Total height of boys = 5635 - 2265 = 3370 Mean height of 20 boys = 3370 ÷ 20 = 169 cm

186. How many second in five minutes?

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Answer: 300

Explanation 1 minute = 60 seconds So, 5 minutes = 5 × 60 = 300 seconds

187. A cell phone can receive 120 messages per minute. At this rate, how many messages can the phone receive in 150 seconds?

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Answer: 300

Explanation To convert minutes to seconds: 1 minute = 60 seconds 120 messages/minute = 120 messages/60 seconds = 2 messages/second For 150 seconds: 2 messages/second * 150 seconds = 300 messages

188. A person walks 10 m North, then turns left and walks 10 m, then turns left and walks 5 m, then turns left and walks 15 m. How far is he from the starting point?

Check answer and explanation

Answer: 7.07 m

Explanation Step 1: Define Movements on a Coordinate System Let the starting point be at the origin (0,0) We can track the person's position by adding the vectors of each movement: 10 m North: The position becomes (0.10) Turn left (West) and walk 10 m: The position becomes (10.10) Turn left (South) and walk 5 m: The position becomes (-10, 5) Turn left (East) and walk 15 m: The position becomes (10, 15, 5) = (5, 5) Step 2: Calculate the Straight-Line Distance To find the distance from the starting point (0,0) to the final point (5, 5) , we use the distance formula: d = √(x2 - x1 )^2 + ( y2 - y 1) ^2 d = √(5-0)^2 ( 5-0) ^2 d= √(5^2 + 5^2) d= √(25 + 25) d= √(50) Simplifying the radical gives: d = 5 √2 The person is 5 √2 (which is approximately 7.07 m) away from the starting point. Last updated 05-03-2026

189. If it takes a machine 1/3 of a minute to produce one item, how many items will it produce in 10 minutes?

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Answer: 30

Explanation To determine how many items the machine will produce in 10 minutes : It takes 1/3 minute to produce one item. In 1 minute, the machine produces 3 items (since 1 ÷ 1/3 = 3). In 10 minutes, the machine will produce 3 × 10 = 30 items. So, the machine will produce 30 items in 10 minutes.

190. A train starts moving at 10:15 AM and reaches its destination at 2:30 PM. What is the total time taken for the journey?

Check answer and explanation

Answer: 4 hours 15 minutes

Explanation From 10:15 AM to 2:30 PM: From 10:15 AM to 2:15 PM is 4 hours. From 2:15 PM to 2:30 PM is an additional 15 minutes. Thus, the total time is 4 hours 15 minutes .

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