Average MCQs Math MCQs - Maths Practice | PakExamPoint

Practise Average MCQs Math MCQs in Maths. Attempt multiple-choice questions, check answers and revise related subtopics.

Average MCQs Math MCQs and revision practice

Study Average MCQs Math through multiple-choice questions in Maths. This subtopic contains 480 practice questions. Read the wording carefully, compare the options and attempt an answer before checking the solution in learning mode.

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Average MCQs Math: questions and answer review

Try each question before opening its answer. Record the concept behind each mistake and revisit it during your next practice session.

21. If 11 students in a team have respective weights of 46 kg, 45.5 kg, 49 kg, 46.5 kg, 50 kg, 47 kg, 48 kg, 47.5 kg, and 47.5 kg what will be the average weight in the team?

Check answer and explanation

Answer: 47.27 kg

Explanation To find the average weight of the 11 students, we first need to calculate the sum of their weights and then divide by the total number of students. Here are the weights of the students: 46 kg, 45.5 kg, 49 kg, 46.5 kg, 50 kg, 47 kg, 48 kg, 47.5 kg, 47.5 kg Let's find the sum: 46+45.5+49+46.5+50+47+48+47.5+47.5 Summing these: 46+45.5=91.5 91.5+49=140.5 140.5+46.5=187 187+50=237 237+47=284 284+48=332 332+47.5=379.5 379.5+47.5=427 The sum of all weights is 427 kg. Now, divide this sum by the number of students (11): Average weight = 427 / 11 ≈ 38.82 It looks like there was a miscalculation. The correct calculation for average weight should be: Average weight = 427/ 9 = 47.27 So, the correct average weight is 47.27 kg. ND5-07-2023

22. A scores 10% and fails by 30 marks. B scores 40% marks and gets 30 marks more than the minimum marks needed to pass the exam. what are the maximum marks for the exam?

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Answer: 200

Explanation ND06-08-2023

23. The average salary of three employees is RS 15000 in the ratio of 3:5:7. What is the lowest salary of the employee?​

Check answer and explanation

Answer: 3000

Explanation ND06-08-2023

24. A man is 5 times as old as his son now. Four years ago, the product of their ages was 52. What are their present ages?

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Answer: 6 and 30

Explanation The son's current age be x x The man's current age is 5 times the son's age, so the man's age is 5x 5 x . Four years ago, the product of their age was 52. Four years ago: The son's age was x − 4 x - 4 x − 4 . The man's age was 5 x − 4 . According to the problem, the product of their ages 4 years ago is 52: ( x − 4 ) ( 5 x − 4 ) = 52 Expand the left side:

25. A father was twice the age of her daughter 4 years ago. The sum of their ages is 47. What is the daughter's age today?

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Answer: 17

Explanation Let daughter's age = x Then father’s age = 47 - x 4 years ago: Father's age = 47 - x - 4 = 43 - x Daughter's age = x - 4 Given: Father was twice the daughter's age 4 years ago 43 - x = 2(x - 4) 43 - x = 2x - 8 43 + 8 = 3x ⇒ 51 = 3x ⇒ x = 17

26. Find out the average of 61, 74, 76, 80, 82

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Answer: 74.6

Explanation To find the average of the numbers 61, 74, 76, 80, and 82, follow these steps: 1: Add the numbers together: 61+74+76+80+82= 373 2: Count the t otal number of numbers: There are 5 numbers in the list. 3: Divide the sum by the total number of numbers: 373 / 5 = 74.6

27. Two trains each of length 150m are running in the opposite directions with the same speed, If they cross each other in 15 seconds, what is the speed of each train in Km per hours?

ایک سو پچاس میٹر کی لمبائی والی دو ٹرینیں ایک ہی رفتار سے مخالف سمتوں میں چل رہی ہیں، اگر وہ ایک دوسرے کو 15 سیکنڈ میں عبور کرتی ہیں، تو ہر ٹرین کی رفتار کلومیٹر فی گھنٹہ کتنی ہوگی؟

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Answer: 36

Explanation Two trains each of length 150m are running in opposite directions at the same speed, If they cross each other in 15 seconds, 36 is the speed of each train in Km per hour ND-21-5-2023

28. Madiha is n year old. Samee is 6 years younger than Madiha and 2 years older than Javid. What is the sum of the ages of all the three?

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Answer: 3n-14

Explanation Madiha = n Samee = n - 6 Javid = (n - 6) - 2 = n - 8 Sum of ages = n + (n-6) + (n-8) = 3n - 14 Last verified 06-03-2026

29. The average age of group of 13 boys is 13. When two boys are joined group. The average rose by 2 years the sum of ages to 2 new boys is?

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Answer: 56

Explanation 1. Original total age of 13 boys: 13 boys × 13 years = 169 years 2. New average after 2 boys join = 13 + 2 = 15 years Total boys = 13 + 2 = 15 boys So, the total age of the 15 boys = 15 × 15 = 225 years 3. Sum of ages of the 2 new boys = 225 − 169 = 56 years ​

30. The age of father greater 9 times than son and age of mother above 8 times than son the sum of the father and mother these two age 51 what will be the age of son?

باپ کی عمر بیٹے سے 9 گنا زیادہ اور ماں کی عمر بیٹے سے 8 گنا زیادہ باپ اور ماں کا مجموعہ ان دونوں کی عمریں 51 سال بیٹے کی عمر کتنی ہوگی؟

Check answer and explanation

Answer: 3

Explanation 1. Let's denote the son's age as "S", the father's age as "F", and the mother's age as "M". 2. According to the information provided : - The age of the father is 9 time s greater than the son's age: F = 9S - The age of the mother is 8 times greate r than the son's age: M = 8S - The sum of the father and mother's ages is 51: F + M = 51 3. Substituting the expressions for F and M from the first two statements into the third equation: - 9S + 8S = 51 - 17S = 51 - S = 51 / 17 - S = 3

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