100 Most Repeated MCQs of Math MCQs - Maths Practice | PakExamPoint

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100 Most Repeated MCQs of Math MCQs and revision practice

Study 100 Most Repeated MCQs of Math through multiple-choice questions in Maths. This subtopic contains 1095 practice questions. Read the wording carefully, compare the options and attempt an answer before checking the solution in learning mode.

Use these 100 Most Repeated MCQs of Math MCQs to identify the facts, rules or methods you need to revise. Where an explanation is available, work through it and write down why your chosen option was correct or incorrect. Revisit difficult questions after reviewing your notes, then use exam mode for timed practice.

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100 Most Repeated MCQs of Math: questions and answer review

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171. A bus has exactly six stops on its route. The bus first stops one and then at stops two, three, four, five, and six respectively. After the bus leaves stop six, the bus turns and returns to stop one and repeats the cycle. The stops are at six building that are, in alphabetical order L,M,N,O,P and Q P is the third stop M is the sixth stop. The stop O is the stop immediately before Q. N is the stop immediately before L. Question: In case L is the second Stop, which among the following must be the stop immediately before M?

Check answer and explanation

Answer: Q

Explanation Question: In case N is the fourth stop, which among the following must be the stop immediately before P? Answer: Q Question: In case a passenger gets on the bus at O, rides past one of the stops, and get off at P, which of the following must be true? Answer: O is stop one

172. A fruit seller had some apples. He sells 40% apples and still has 420 apples. Originally, he had _____?

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Answer: 700

Explanation Given data : The seller sells 40% of his apples. After selling, he still has 420 apples. Concept/Formula : The concept used to solve this problem is related to "percentage". The seller was left with 60% of his apples (100% - 40% = 60%) when he had 420 apples left. Solution : ⇒ the 420 apples represent 60% of his original stock (since he sold 40%). ⇒ If 60% of the original stock equals 420 apples, then 1% can be calculated by dividing 420 by 60. Hence, 1% = 420 ÷ 60 = 7 apples. ⇒ Now, to find the total original stock (100%), the amount per 1% is multiplied by 100. Therefore, the original amount = 7 × 100 = 700 apples. Therefore, originally, he had 700 apples.

173. If log2 = 0.3010 and 3=0.4771, the value of log5 512 is?

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Answer: 3.876

Explanation l o g 5 ​ 5 1 2 = l o g 5 l o g 5 1 2 ​ = l o g ( 1 0 / 2 ) l o g 2 9 ​ = l o g 1 0 − l o g 2 9 l o g 2 ​ = 1 − 0 . 3 0 1 0 9 × 0 . 3 0 1 0 ​ = 0 . 6 9 9 2 . 7 0 9 ​ = 6 9 9 2 7 0 9 ​ = 3 . 8 7 6

174. The straight angle is ____?

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Answer: 180°

Explanation In Maths, a straight angle is an angle equal to 180° . It is called straight because it appears as a straight line.

175. Distance between points (2,3) and (7,3) is ______?

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Answer: 5

Explanation To find the distance between two points, use the distance formula: Distance = √((x₂ - x₁)² + (y₂ - y₁)²) Given points: (x₁, y₁) = (2, 3) (x₂, y₂) = (7, 3) Substitute the values: Distance = √((7 - 2)² + (3 - 3)²) = √((5)² + 0²) = √(25) = 5

176. 150% of 15 + 75% of 75 = ?

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Answer: 78.75

Explanation 150% of 15 + 75% of 75 = ? =3/2*15+3/4*75 =22.5+56.25 78.75

177. The school have 90 male teachers out of 150. What is the percentage of female teacher ?

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Answer: 40 %

Explanation MALE TEACHER= 90 TOTAL =150 150-90=60 SO FEMALE TEACHER=60 NOW 90/150x100=60% MALE TEACHER 60/150x100=40% FEMALE TEACHER

178. A2+B2=? ,if A-B=9 AB=3

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Answer: 87

Explanation a-b=9 square both sides (a-b)2= 9 (a-b)2=(9)2 A2-B2-2ab=81 A2-B2-2(3)=81 A2-B2=81+6 A2-B2=87

179. 9 is 1/3% of what number?

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Answer: 2700

Explanation Since 9 is 1/3% of x: 9 = (1/3)/100 × x 9 = (1/300) × x Multiply both sides by 300: 2700 = x

180. The number of diagnosis of a 12 sided figure is _____?

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Answer: 54

Explanation The number of diagonals in a polygon can be calculated using the formula: n(n-3)/2 where n is the number of sides. For a 12-sided polygon (dodecagon): n = 12 Number of diagonals = 12(12-3)/2 = 12(9)/2 = 108/2 = 54

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