According to Crystal Field Theory (CFT) in a strong field, how many unpaired electrons are in [ 𝐹 𝑒 ( 𝑁 𝐻 3 ) 6 ] 2 + ?
FPSC 5 Years Past Papers Subject Wise (Solved With Details) / All — Multiple-choice practice
- A. None of these
- B. 1
- C. 2
- D. 0
Correct answer
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Explanation
Explanation In the complex [ 𝐹 𝑒 ( 𝑁 𝐻 3 ) 6 ] ^2 + , iron (Fe) is in the +2 oxidation state, meaning it has a 𝑑 6 electron configuration. Ammonia (NH₃) is considered a strong field ligand under Crystal Field Theory (CFT), causing the electrons in the 𝑑 -orbitals to pair up due to the large splitting of the 𝑑 -orbitals. In a strong field environment, the electrons occupy the lower energy 𝑡 2 𝑔 orbitals first, and all six electrons pair up, leaving no unpaired electrons. Therefore, the number of unpaired electrons is 0.
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