A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
FPSC 5 Years Past Papers Subject Wise (Solved With Details) / All — Multiple-choice practice
- A. None of these
- B. 2/7
- C. 10/21
- D. 4/7
Correct answer
10/21
Explanation
Explanation Probability = 5C2/7C2 = 10/21 Total number of balls = 2 + 3 + 2 = 7 ∴ Number of ways of drawing 2 balls out of 7 = 7C2 = (7 × 6) / (2 × 1) = 42/2 = 21 Number of balls other than blue = 5 ∴ Number of ways of drawing 2 balls out of 5 = 5C2 = (5 × 4) / (2 × 1) = 20/2 = 10 ∴ Required Probability = 10/21
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