Find the largest number which divides 615 and 963 leaving remainder 6 in each case.

Correct answer

87

Explanation

Explanation we have to find the largest number which divide 6 1 5 and 9 6 3 leaving remainder 6 in each case. so let us subtract 6 from 6 1 5 and 9 6 3 ⇒ 6 1 5 − 6 = 6 0 9 ⇒ 9 6 3 − 6 = 9 5 7 now lets find the H C F ⇒ prime factorisation of 6 0 9 = 2 9 × 3 × 3 prime factorisation of 9 5 7 = 2 9 × 3 × 1 1 now lets take out the common factors from both the cases ⇒ 2 9 and 3 x = 2 9 × 3 = 8 7 ∴ 8 7 is the number which will divide 6 1 5 and 9 6 3 leaving remainder 6 in each case. **** RY18012023