A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is ______?
Lecturer Physics Past Papers and Syllabus / All — Multiple-choice practice
- A. 1 Hz
- B. 2 Hz
- C. 3 Hz
- D. None of these
Correct answer
1 Hz
Explanation
Explanation To find the frequency, we can use the equation: v_max = A * ω where v_max = 31.4 cm/s, A = 5 cm ω = v_max / A = 31.4 cm/s / 5 cm = 6.28 rad/s Now, ω = 2 * π * f f = ω / (2 * π) = 6.28 rad/s / (2 * π) = 1 Hz
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