If a spherical ball rolls on a table without slipping, the fraction of its total energy associated with rotation is ______?
Lecturer Physics Past Papers and Syllabus / All — Multiple-choice practice
- A. 2/7
- B. None of these
- C. 3/7
- D. 1/7
Correct answer
2/7
Explanation
Explanation When a spherical ball rolls without slipping: Total energy (E) = Kinetic energy (K) + Rotational energy (U) K = (1/2)mv^2 U = (1/2)Iω^2 = (1/5)mv^2 (for a sphere) E = K + U = (1/2)mv^2 + (1/5)mv^2 = (7/10)mv^2 Fraction of energy associated with rotation: U/E = ((1/5)mv^2) / ((7/10)mv^2) = 2/7
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