Calculate the moment of inertia of the earth about its diameter, taking it to be a sphere of 10^25kg and diameter 12800 km?
Lecturer Physics Past Papers and Syllabus / All — Multiple-choice practice
- A. None of these
- B. 1.64 kgm^3
- C. 0
- D. 1.64 × 10^38kgm^3
Correct answer
1.64 × 10^38kgm^3
Explanation
Explanation To calculate the moment of inertia of the Earth about its diameter, we can use the formula for the moment of inertia of a sphere: I = (2/5)MR^2 where: I = moment of inertia M = mass of the Earth (10^25 kg) R = radius of the Earth (diameter/2 = 12800 km / 2 = 6400 km = 6.4 × 10^6 m) Plugging in the values, we get: I = (2/5) × 10^25 kg × (6.4 × 10^6 m)^2 = (2/5) × 10^25 kg × 4.096 × 10^13 m^2 = 1.6384 × 10^38 kg m^2 ≈ 1.64 × 10^38 kg m^2
Continue with All MCQs, explore all Lecturer Physics Past Papers and Syllabus topics, or try the All practice quiz.
More All questions
- Velocity of sound is greatest in ______?
- What is the work function of the metal if the light of wavelength 4000λ generates photo electrons of velocity 6 × 10^5 ms^-1 from it?
- The atomic diameter of a BCC crystal (if a is lattice parameter) is _____?
- Darfur conflict is in ______?
- Wheatstone bridge is ______?
- The professor told her student about the project months in advance so that they would have_____time to complete their work.
Found an error? Report a correction with this page URL and a supporting source.