A force of 15N is applied at a distance of 0.4 meters from a pivot. The torque would be ______?

IBA STS Screening Test Bps 05 to 15 Past Papers and Syllabus / All — Multiple-choice practice

  1. A. 6 Nm
  2. B. 4 Nm
  3. C. None of these
  4. D. 10 Nm

Correct answer

6 Nm

Explanation

Explanation Torque = Force × Distance = 15 N × 0.4 m = 6 Nm

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