When the angle of refraction is 90° and the refractive index for water is 1. 33, the critical angle is ______?
General Science / Physics Class 10th MCQs — Multiple-choice practice
- A. 50.0°
- B. 48.8°
- C. 49.1°
- D. 51.0°
Correct answer
48.8°
Explanation
Explanation The critical angle is the angle of incidence above which total internal reflection occurs. It can be calculated using Snell's law: n1 sin(θ1) = n2 sin(θ2) where n1 = 1.33 (refractive index of water), θ1 = critical angle, n2 = 1 (refractive index of air), and θ2 = 90° (angle of refraction). Rearranging the equation to solve for θ1, we get: θ1 = arcsin(n2 / n1) Substituting the values, we get: θ1 = arcsin(1 / 1.33) ≈ 48.8° So, the critical angle is approximately 48.8°.
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